# Difference between revisions of "In slide 9, why did you only linearize around the downward equilibrium point?"

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Linearization was also done around the upward equilibrium point by using the small angle approximation of the sine function. This could be done in the upward case because the equilibrium point that we are linearizing around is zero; for the downward case, our equilibrium point was $\pi$ and so we weren't able to use that approximation. | Linearization was also done around the upward equilibrium point by using the small angle approximation of the sine function. This could be done in the upward case because the equilibrium point that we are linearizing around is zero; for the downward case, our equilibrium point was $\pi$ and so we weren't able to use that approximation. | ||

− | --[[User:Braman|Braman]] 16:09, 6 October 2008 (PDT) | + | --[[User:Braman|Julia Braman]] 16:09, 6 October 2008 (PDT) |

[[Category: CDS 101/110 FAQ - Lecture 2-1]] | [[Category: CDS 101/110 FAQ - Lecture 2-1]] | ||

[[Category: CDS 101/110 FAQ - Lecture 2-1, Fall 2008]] | [[Category: CDS 101/110 FAQ - Lecture 2-1, Fall 2008]] |

## Latest revision as of 23:10, 6 October 2008

Linearization was also done around the upward equilibrium point by using the small angle approximation of the sine function. This could be done in the upward case because the equilibrium point that we are linearizing around is zero; for the downward case, our equilibrium point was $\pi$ and so we weren't able to use that approximation.

--Julia Braman 16:09, 6 October 2008 (PDT)